A - Two IntegersXがYの倍数でなければXが答えになる. #include <iostream> using namespace std; int main(void) { int x, y; cin >> x >> y; if(x % y == 0) { cout << -1 << endl; return 0; } cout << x << endl; } B - Two Arrays操作回数は(bの総和) - (aの総和)</iostream>…